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Q.

In which of the following arrangements, the given sequence is not strictly according to the properties indicated against it?

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a

B < Be < C < O : Increasing first ionization enthalpy

b

I < Br < Cl< F: Negative electron gain enthalpy

c

Mg2+<Na+<F<O2. Increasing ionic radii

d

C < N < O < F: Increasing electronegativity 

answer is B.

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Detailed Solution

Due to filled outer orbital  2s2,Be  has more ionization enthalpy than B
Due to high electron density of F-atom, there is more repulsion between coming electron. So, electron affinity of F is lesser than Cl.
 ΔegH:Cl>F>Br>I
For monoatomic isoelectronic ions, more the number of protons lesser will be ionic size
 

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