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In which of the following compounds, oxygen exhibits $+ 2$ oxidation state ?

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$H_{2} O$

$H_{2} O_{2}$

$O F_{2}$

$H_{2} {SO}_{4}$

answer is C.

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Detailed Solution

In $H_{2} O$ and $H_{2} {SO}_{4}$ , oxygen has $- 2$ oxidation state.

In $H_{2} O_{2}$ , oxygen is present as peroxide and it has $- 1$ oxidation state.

In ${OF}_{2}$ , it is less electronegative than fluorine,

$\Rightarrow x + (- 2) = 0 \Rightarrow x = + 2$

So, oxygen is in $+ 2$ oxidation state.

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