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In which of the following reaction $H 2 O 2$ acts as a reducing agent?
(P) $H 2 O 2 + 2 H + + 2 e − → 2 H 2 O$
(Q) $H 2 O 2 − 2 e − → O 2 + 2 H +$
(R) $H 2 O 2 + 2 e − → 2 O H −$
(S) $H 2 O 2 + 2 O H − − 2 e − → O 2 + 2 H 2 O$

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P,Q

P,R

Q,S

R,S

answer is B.

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Detailed Solution

reducing agent undergoes oxidation

Oxidation number of oxygen increases from -1 to zero

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