In which of the following reaction(s) H2O2 can convert the underlined atom into the product with oxidation state = + 6 ?

S _ O 2 + H 2 O 2 + OH - → , Cr __ Cl 3 + H 2 O 2 + OH - →

A) CrCl 3 → Na 2 CrO 4 B) K 2 Cr 2 O 7 → CrO 5 C) SO 2 → SO 4

K 2 Cr 2 __ O 7 + H 2 O 2 + H 2 SO 4

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In which of the following reaction(s) H₂O₂ can convert the underlined atom into the product with oxidation state = + 6 ?

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$\underline{S} O_{2} + H_{2} O_{2} + {OH}^{-} \to$

$H_{2} O_{2} + {Na}_{3} {AsO}_{3} + {OH}^{-} \to$

$\underset{__}{Cr} {Cl}_{3} + H_{2} O_{2} + {OH}^{-}$ $\to$

$K_{2} \underset{__}{{Cr}_{2}} O_{7} + H_{2} O_{2} + H_{2} {SO}_{4}$

answer is A, C.

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A) CrCl₃ $\to$ Na₂CrO₄
B) K₂Cr₂O₇ $\to$ CrO₅
C) SO₂ $\to$ SO₄

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