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In which of the following reactions $H_{2} O_{2}$ is a reducing agent ?

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$2 {FeCl}_{2} + 2 HCl + H_{2} O_{2} \to 2 {FeCl}_{2} + H_{2} O$

${Cl}_{2} + H_{2} O_{2} \to 2 HCl + O_{2}$

$2 HI + H_{2} O_{2} \to 2 H_{2} O + I_{2}$

$H_{2} {SO}_{3} + H_{2} O_{2} \to H_{2} {SO}_{4} + H_{2} O$

answer is B.

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Detailed Solution

$\overset{0}{{Cl}_{2}} + H_{2} O_{2} \to 2 H \overset{- 1}{Cl} + O_{2}$ . In this reaction chlorine is reduced from zero to - 1 oxidation state.

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