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Q.

In which of the following solvents should KCl be soluble at 25°C ?(D = Dielectric constant value)

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a

C6H6[D = 0]

b

CH3COCH3[D = 2]

c

CCl4[D = 0]

d

CH3OH[D = 32]

answer is D.

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Detailed Solution

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Ionic substances are soluble in polar solvents. Greater the dielectric constant of the solvent higher will be the solubility of the ionic substance.

Thus solubility of KCl in

CH3OH>CH3COCH3>C6H6=CCl4

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