In which of the following solvents should $KCl$ be soluble at $25 ° C$ ? (D= Dielectric constant value)

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${CCl}_{4} [D = 0]$

$C_{6} H_{6} [D = 0]$

${CH}_{3} OH [D = 32]$

${CH}_{3} {COCH}_{3} [D = 2]$

answer is D.

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Detailed Solution

Like dissolves like. Since KBr is a polar ionic compound, it will be soluble in a polar solvent. The solvent with a higher value of dielectric constant will provide maximum solubility. It will be most soluble in polar solvents, i.e. with the highest value of D.

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