In which of the following the ratio of hybrid and pure Orbitals is same

I) $C{H}_2=C{H}_2$

II)

III) $C{H}_2=C=C{H}_2$

IV) $CH\equiv CH$

Ethene has two sp2 carbons so, total 6 HO, 4 Hydrogen and two p are pure, so 6 PO are pure. In allene they are two sp2 carbons and one sp. Hence HO are 8. Pure orbitals from carbon are 4 and hydrogen 4. Hence total HO=8, Pure =8.