In which reaction, product (major) formation takes by Hofmann rule?

I) $C{H}_3-C{H}_{2}CHBr-C{H}_3\stackrel{{\left(C{H}_3\right)}_{3}COK/\Delta }{\to }$

II)  $C{H}_3-C{H}_2-\stackrel{\stackrel{F}{|}}{CH}-C{H}_3\underset{alcKOH}{\overset{\Delta }{\to }}$

III) $C{H}_3-C{H}_2-\stackrel{\stackrel{Br}{|}}{CH}-C{H}_3\underset{ }{\overset{C{H}_{3}ONa/\Delta }{\to }}$

Select the correct answer from the codes Given below:

I and II ----- Hofmann product ; III---Saytzeff product

In reaction I, bulky base favors Hofmann product.

In reaction II, F is not a good leaving group and the reactant undergoes E₁CB mechanism to form a carbanion intermediate, resulting in the formation of Hofmann product.