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Q.

In YDSE, a source of wavelength 6000 $\overset{0}{A}$ is used. The screen is placed 1 m from the slits. Fringes formed on the screen, are observed by a student sitting close to the slits. The student's eye can distinguish two neighboring fringes. If they subtend an angle more than 1 minute of arc. What will be the maximum distance between the slits so that the fringes are clearly visible

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a

$2.06 c m$

b

$2.06 m m$

c

$2.06 \times 10^{- 3} m m$

d

$N o n e o f t h e s e$

answer is A.

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Detailed Solution

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$A c c o r d i n g t o g i v e n p r o b l e m a n g u l a r f r i n g e w i d t h θ = \frac{λ}{d} \geq \frac{π}{180 \times 60} [A s 1 ’ = \frac{π}{180 \times 60} r a d] \Rightarrow d < \frac{6 \times 10^{- 7} \times 180 \times 60}{π} \Rightarrow d < 2.06 \times 10^{- 3} m \Rightarrow d_{\max} = 2.06 m m$

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