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Q.

In YDSE, if a bichromatic light having wavelengths 400 nm and 600 nm is used, the maxima due to both light will overlap at a certain distance Y from the central maxima. If the separation between the slit is 1 mm and distance between the screen and slits is 1 m, then Y is equal to ______ mm

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answer is 1.2.

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Detailed Solution

The maxima will be at Y=LCM of λ1Dd and λ2Dd

=LCM  (400×10−6  and  600×10−6)

=1200×10−6m=1.2  mm

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