In YDSE, if the maximum intensity is I₀, then what is the intensity at a point where optical path difference between the waves coming from two slits is $λ$ /4

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I_o

4I_o

I_o/2

I_o/4

answer is C.

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Detailed Solution

$I = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}} \cos ϕ$
Where $ϕ = \frac{2 π}{λ} Δx; Here, I_{1} = I_{2} = I_{0} / 4$
And for $Δx = \frac{λ}{4}, ϕ = \frac{π}{2} \Rightarrow I = \frac{I_{0}}{2}$

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