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Q.

In YDSE, the two slits are separated by 0.1 mm and they are 0.5m from the screen. The wavelength of light used is 5000 $\overset{o}{A}$ . Then the distance between 7^th maxima and 11^th minima is

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a

8 mm

b

4.75mm

c

4 mm

d

8.75mm

answer is B.

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Detailed Solution

Given
$d = 0.1 mm = 10^{- 4} m, D = 0.5 m$
$and λ = 5000 A^{0} = 5.0 \times 10^{- 7} m$
$Δy = {(y_{11})}_{dark} - {(y_{7})}_{bright} = \frac{(2 \times 11 - 1) λD}{2 d} - \frac{7 λD}{d}$
$Δ y = \frac{7 λ D}{2 d} = \frac{7 \times 5.0 \times 10^{- 7} \times 0.5}{2 \times 10^{- 4}} = 8.75 \times 10^{- 3} m$
$Δ y = 8.75 mm$

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In YDSE, the two slits are separated by 0.1 mm and they are 0.5m from the screen. The wavelength of light used is 5000Ao . Then the distance between 7th maxima and 11th minima is