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Q.

In YDSE the wavelength used is 600 nm. A transparent slice of thickness 36 micrometer is placed in the path of one wave. The central fringe shifts to 30th bright fringe from the centre then the value of refractive index of the slice is x2  ,then x= _______.

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answer is 3.

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Detailed Solution

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nλ=t(μ−1)

30 × 600 × 10-9= 36 × 10-6× (μ-1) =18×10−636×10−6= .5

⇒   μ=1=.5⇒μ=1.5

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