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Q.

In Young’s double slit experiment a slit is covered with thin film so that the optical path difference introduced between coherent waves is 5λ.  Now the new position of central maximum will be at

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a

the initial position of 2nd minimum

b

the initial position of 3rd maximum

c

the initial position of 3rd minimum

d

the initial position of 5th maximum

answer is A.

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Detailed Solution

Shift in central maximum = ΔxDd=5λDd          =nλDd

n = 5

The distance of 5th maximum from central maximum is 5λDd

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