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Q.

In Young's double slit experiment, find the minimum distance on the screen from the position of central maximum for which the intensity is half the maximum intensity.  (λ=500nm,d=1mn,D=1m)

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a

3.25×10-4m

b

1.25×10-4m

c

1.25m

d

5×10-4m

answer is B.

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Detailed Solution

Use  y=λD4d,β=λDd,y=β4⇒1.25×10−4m

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In Young's double slit experiment, find the minimum distance on the screen from the position of central maximum for which the intensity is half the maximum intensity.  (λ=500nm,d=1mn,D=1m)