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In Young’s double slit experiment, the 10^th maximum of wavelength $λ_{1}$ is at a distance of $y_{1}$ from the central maximum. When the wavelength of the source is changed to $λ_{2}$ , 5^th maximum is at a distance of $y_{2}$ from its central maximum. The ratio $(\frac{y_{1}}{y_{2}})$ is

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$\frac{2 λ_{1}}{λ_{2}}$

$\frac{2 λ_{2}}{λ_{1}}$

$\frac{λ_{1}}{2 λ_{2}}$

$\frac{λ_{2}}{2 λ_{1}}$

answer is A.

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Detailed Solution

$\frac{y_{1}}{y_{2}} = \frac{Δ x_{1}}{Δ x_{2}} = \frac{n_{1} λ_{1}}{n_{2} λ_{2}}$

$\frac{y_{1}}{y_{2}} = \frac{10 λ_{1}}{5 λ_{2}} = \frac{2 λ_{1}}{λ_{2}}$

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