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In young’s double slit experiment, the 10^th maximum of wavelength $λ_{1}$ is at a distance of $y_{1}$ from the central maximum. When the wavelength of the source is changed to $λ_{2}$ , 5^th maximum is at a distance of $λ_{2}$ from its central maximum. The ratio $(\frac{y_{1}}{y_{2}})$ is

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$\frac{2 λ_{1}}{λ_{2}}$

$\frac{2 λ_{2}}{λ_{1}}$

$\frac{λ_{1}}{2 λ_{2}}$

$\frac{λ_{2}}{2 λ_{1}}$

answer is A.

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Detailed Solution

$y_{1} = 10 \frac{λ_{1} D}{d}$

$y_{2} = \frac{5 λ_{2} D}{d}$

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