In Young's double slit experiment, the 8th maximum with wavelength λ1 is at a distance d1 from the central maximum and the 6th maximum with a wavelength λ2 is at a distance d2. Then (d1/d2) is equal to

Position of nth maxima from central maxima is given by xn=nλDd⇒xn∝nλ⇒d1d2=n1λ1n2λ2=8λ16λ2=43λ1λ2

In Young's double slit experiment, the 8th maximum with wavelength λ1 is at a distance d1 from the central maximum and the 6th maximum with a wavelength λ2 is at a distance d2. Then (d1/d2) is equal to

Position of nth maxima from central maxima is given by xn=nλDd⇒xn∝nλ⇒d1d2=n1λ1n2λ2=8λ16λ2=43λ1λ2

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In Young's double slit experiment, the 8th maximum with wavelength $λ_{1}$ is at a distance d₁ from the central maximum and the 6th maximum with a wavelength $λ_{2}$ is at a distance d₂. Then (d₁/d₂) is equal to

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$\frac{4}{3} (\frac{λ_{2}}{λ_{1}})$

$\frac{4}{3} (\frac{λ_{1}}{λ_{2}})$

$\frac{3}{4} (\frac{λ_{2}}{λ_{1}})$

$\frac{3}{4} (\frac{λ_{1}}{λ_{2}})$

answer is B.

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Position of nth maxima from central maxima is given by $x_{n} = \frac{nλD}{d}$

$\Rightarrow x_{n} \propto nλ \Rightarrow \frac{d_{1}}{d_{2}} = \frac{n_{1} λ_{1}}{n_{2} λ_{2}} = \frac{8 λ_{1}}{6 λ_{2}} = \frac{4}{3} (\frac{λ_{1}}{λ_{2}})$

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In Young's double slit experiment, the 8th maximum with wavelength λ1 is at a distance d1 from the central maximum and the 6th maximum with a wavelength λ2 is at a distance d2. Then (d1/d2) is equal to

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In Young's double slit experiment, the 8th maximum with wavelength $λ_{1}$ is at a distance d₁ from the central maximum and the 6th maximum with a wavelength $λ_{2}$ is at a distance d₂. Then (d₁/d₂) is equal to