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Q.

In Young’s double slit experiment, the slit widths are in ratio 1:25. The ratio of intensity at maxima and minima in the interference pattern is

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a

3:2

b

1:5

c

1:25

d

9:4

answer is C.

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Detailed Solution

$\frac{I_{\max}}{I_{\min}} = \frac{{(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2}}{{(\sqrt{I_{2}} - \sqrt{I_{1}})}^{2}} = \frac{{(1 + \sqrt{\frac{I_{1}}{I_{2}}})}^{2}}{{(1 - \sqrt{\frac{I_{1}}{I_{2}}})}^{2}} G i v e n \frac{ω_{1}}{ω_{2}} = \frac{1}{25} = \frac{I_{1}}{I_{2}} \frac{I_{\max}}{I_{\min}} = \frac{\frac{36}{25}}{\frac{16}{25}} = 9 : 4$

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