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Q.

In Young’s double slit experiment, the slit widths are in ratio 1:25. The ratio of intensity at maxima and minima in the interference pattern is

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a

3:2

b

1:5

c

1:25

d

9:4

answer is C.

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Detailed Solution

ImaxImin=(I1+I2)2(I2−I1)2=(1+I1I2)2(1−I1I2)2 Given   ω1ω2=125=I1I2    ImaxImin=36251625=9:4

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