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Q.

In Young’s double slit experiment, the two slits are covered by slabs of same thickness but refractive index 1.4 and 1.7 the distance between slits and screen is 1m and distance between slits is 1mm and wavelength of coherent source used is $4000 A^{0}$ and the central fringe shifts to the 3^rd bright fringe position, then

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a

Shift will be towards slab of Refractive index 1.4 by 1.2 mm.

b

Shift will be towards slab of Refractive index 1.7 by 1.2 mm.

c

Slabs are of thickness $4 A^{0}$

d

Slabs are of thickness $4 μ m$

answer is A, C.

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Detailed Solution

$Δ x = \frac{D}{d} (μ_{2} - μ_{1}) t = 3 \frac{λ D}{d} Δ x = \frac{1}{10^{- 3}} \times 0.3 \times 4 \times 10^{- 6} = 1.2 m m t = \frac{3 \times 4 \times 10^{- 7}}{0.3} = 4 μ m Δ x = \frac{1}{10^{- 3}} \times 0.3 \times 4 \times 10^{- 6} = 1.2 m m$

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