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In Young’s double slit experiment, we get 60 fringes in the field of view of monochromatic light of wavelength $4000 Å$ . If we use monochromatic light of wavelength $6000 Å,$ then the number of fringes obtained in the same field of view is

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Detailed Solution

$n_{1} λ_{1} = n_{2} λ_{2} \Rightarrow 60 \times 4000 = n_{2} \times 6000 \Rightarrow n_{2} = 40$

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