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Q.

In Young's double slit interference experiment, the distance between two secondary sources is 0.1πmm . The distance of the screen from the secondary sources is 25 cm. Wavelength of light used is 6000A0 . Then what is the angular position of the first dark fringe (in degrees) ?

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answer is 0.54.

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Detailed Solution

 Question Image
The angular position   θ=βD=λd(β=λDd) 
The first dark fringe will be at half the fringe width from the mid-point of central maximum. Thus the angular position of first dark fringe will be
 α=θ2=12[λd]=12  [6000×π0.1×103×1010]180π=0.540
 

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