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In Young’s double slits experiment, the position of 5^th bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1m and wavelength of used monochromatic light is 600 nm. The separation between the slits is :

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36µm

48µm

12µm

60µm

answer is B.

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Detailed Solution

Position of 5^th bright,

$\frac{5 Dλ}{d} = 5 \times 10^{- 2} m;$

$λ = 600 \times 10^{- 9} m = 6 \times 10^{- 7} m$

$D = 1 m, d = ?$

$d = \frac{5 Dλ}{5 \times 10^{- 2}} = \frac{6 \times 10^{- 7}}{10^{- 2}} = 60 μm$

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