In Young's double slit arrangement, the 7th maximum with wavelength λ1 is at a distance d1. and that with wavelength λ2 is at a distance d2 Then d1/d2 is

7β1=d1=7λ1Dd and 7β2=d2=7λ2Dd d1d2=λ1λ2

In Young's double slit arrangement, the 7th maximum with wavelength λ1 is at a distance d1. and that with wavelength λ2 is at a distance d2 Then d1/d2 is

7β1=d1=7λ1Dd and 7β2=d2=7λ2Dd d1d2=λ1λ2

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In Young's double slit arrangement, the 7th maximum with wavelength $λ$ ₁ is at a distance $d_{1}$ _.and that with wavelength $λ$ ₂is at a distance d₂Then d₁/d₂is

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$\frac{λ_{1}^{2}}{λ_{2}^{2}}$

$\frac{λ_{2}^{2}}{λ_{1}^{2}}$

$\frac{λ_{1}}{λ_{2}}$

$\frac{λ_{2}}{λ_{1}}$

answer is C.

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$7 β_{1} = d_{1} = 7 \frac{λ_{1} D}{d} and 7 β_{2} = d_{2} = 7 \frac{λ_{2} D}{d} \frac{d_{1}}{d_{2}} = \frac{λ_{1}}{λ_{2}}$

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In Young's double slit arrangement, the 7th maximum with wavelength λ1 is at a distance d1. and that with wavelength λ2 is at a distance d2 Then d1/d2 is

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In Young's double slit arrangement, the 7th maximum with wavelength $λ$ ₁ is at a distance $d_{1}$ _.and that with wavelength $λ$ ₂is at a distance d₂Then d₁/d₂is