In Young's double slit experiment, a thin film of thickness t having refractive index μ is introduced in front of one of the slits. It is observed that the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t under the given observation should be : (λ is wavelength of the light used)

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$\frac{λ}{2 (μ - 1)}$

$\frac{2 λ}{(μ - 1)}$

$\frac{λ}{(μ - 1)}$

$\frac{λ}{(4 μ - 1)}$

answer is B.

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Detailed Solution

$\begin{array}{l} Δy = (μ - 1) \frac{tD}{d} = β = \frac{λD}{d} \\ t = \frac{λ}{(u - 1)} \end{array}$

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