In Young's double slit experiment, angular width of fringes is 0.20^o for sodium light of wavelength 5890 Å. If complete system is dipped in water, then angular width of fringes becomes

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0.11°

0.15°

0.22°

0.30°

answer is B.

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Detailed Solution

$Angular fringe width θ = \frac{λ}{d} \Rightarrow θ \propto λ λ_{w} = \frac{λ_{a}}{μ_{w}} So θ_{w} = \frac{θ_{air}}{μ_{w}} = \frac{0 .20}{\frac{4}{3}} = 0 {.15}^{\circ}$

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