In Young’s double slit experiment, distance between the slits is d and that between the slits and screen is D. Angle between principle axis of lens and perpendicular bisector of $S_{1} and S_{2} is 45^{\circ}$ . The point source S is placed at the focus of lens and aperture of lens is much larger than d. Assuming only the reflected light from plane mirror M is incident on slits, distance of central maxima from O will be :

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$\frac{D}{\sqrt{3}}$

$\frac{D}{\sqrt{4}}$

$\frac{D}{\sqrt{2}}$

answer is C.

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Central maximum always along the incident rays on the screen crossing through the slits.

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