Wavelength of light used is inversely proportional to number of fringes observed as increase in wavelength increases the fringe width and hence, the number of fringe will decrease.

$$\begin{gathered} \therefore {\lambda }_{\mathrm{s}}{\mathrm{n}}_{\mathrm{s}}={\lambda }_{\mathrm{g}}{\mathrm{n}}_{\mathrm{g}} \\ {\mathrm{n}}_{\mathrm{s}}=\frac{{\mathrm{\lambda }}_{\mathrm{g}}{\mathrm{n}}_{\mathrm{g}}}{{\mathrm{\lambda }}_{\mathrm{s}}}=\frac{5461\times 60}{5890}=55.63\approx 55 \end{gathered}$$