In young's double slit experiment, sodium light λ=589 nm is used. Angular separation between adjacent bright fringes is 3.50×10−3 rad. If sodium light is replaced by another light of wavelength 722 nm, what will be the angular separation in this case?

Angular separation between adjacent bright fringes is given by, θ=λd∴ θ1θ=λ1λ⇒θ13.5×10−3=722589⇒θ1=4.29×10−3rad

In young's double slit experiment, sodium light λ=589 nm is used. Angular separation between adjacent bright fringes is 3.50×10−3 rad. If sodium light is replaced by another light of wavelength 722 nm, what will be the angular separation in this case?

Angular separation between adjacent bright fringes is given by, θ=λd∴ θ1θ=λ1λ⇒θ13.5×10−3=722589⇒θ1=4.29×10−3rad

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In young's double slit experiment, sodium light $λ = 589 n m$ is used. Angular separation between adjacent bright fringes is $3.50 \times 10^{- 3}$ rad. If sodium light is replaced by another light of wavelength 722 nm, what will be the angular separation in this case?

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$4.89 \times 10^{- 3} r a d$

$5.2 \times 10^{- 3} r a d$

$2 \times 10^{- 3} r a d$

$4.29 \times 10^{- 3} r a d$

answer is D.

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Detailed Solution

Angular separation between adjacent bright fringes is given by, $θ = \frac{λ}{d}$

$∴ \frac{θ^{1}}{θ} = \frac{λ^{1}}{λ} \Rightarrow \frac{θ^{1}}{3.5 \times 10^{- 3}} = \frac{722}{589} \Rightarrow θ^{1} = 4.29 \times 10^{- 3} r a d$

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In young's double slit experiment, sodium light λ=589 nm is used. Angular separation between adjacent bright fringes is 3.50×10−3 rad. If sodium light is replaced by another light of wavelength 722 nm, what will be the angular separation in this case?

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In young's double slit experiment, sodium light $λ = 589 n m$ is used. Angular separation between adjacent bright fringes is $3.50 \times 10^{- 3}$ rad. If sodium light is replaced by another light of wavelength 722 nm, what will be the angular separation in this case?