In Young's double slit experiment, the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be

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$5000 Å$

$6000 Å$

$7000 Å$

$8000 Å$

answer is A.

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Detailed Solution

$By using x_{n} = \frac{nλD}{d} \Rightarrow (5 \times 10^{- 3}) = \frac{10 \times λ \times 1}{(1 \times 10^{- 3})} \Rightarrow λ = 5 \times 10^{- 7} m = 5000 \overset{0}{A}$

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