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In Young’s double slit experiment two slits are separated by 0.1 mm and they are 0.5 m from screen. The wavelength of light used is 500 nm. The distance between 7^th maxima and 11^th minima on screen is

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6.7 mm

4.3 mm

5.2 mm

8.75 mm

answer is D.

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Detailed Solution

$\begin{array}{l} Δy = (y_{11}) dark - (y_{7}) Bright = \frac{(2 \times 11 - 1) λD}{2 d} - \frac{7 λD}{d} \\ Δy = \frac{7 λD}{2 d} = \frac{7 \times 5 \times 10^{- 7} \times 0 .5}{2 \times 10^{- 4}} = 8 .75 mm \end{array}$

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