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Q.

In young's double slit experiment, when one of the slits is covered with a thin transparent sheet of thickness t and refractive index 1.6. The central bright fringe is shifted by a distance d/4. When the other slit is also covered by a thin transparent sheet of thickness 2t and refractive index μ, the central bright fringe is again sifted to its original position. Then find the value of μ.

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a

1.7

b

1.3

c

1.4

d

1.5

answer is A.

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Detailed Solution

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Net path difference must be zero at the position of central bright fringe

∴ (μ2−1)t2=(μ1−1)t1⇒(μ2−1)×2t=(1.6−1)×t⇒μ2=1.3

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