In Young’s double slit interference experiment the wavelength of light used is 6000A°. If the path difference between waves reaching a point P on the screen is 1.5
microns, then at that point P

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Third bright band occurs

Second bright band occurs

Second dark band occurs

Third dark band occurs

answer is C.

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Detailed Solution

$\begin{array}{l} λ = 6000 A^{0}, x = 1 .5 microns = 1 .5 \times 10^{- 6} m \\ x = nλ, \Rightarrow n = \frac{x}{λ} = \frac{1 .5 \times 10^{- 6}}{6000 \times 10^{- 8}} = 2 .5 \end{array}$
As the n is more than 2, we get third dark band

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