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Q.

In Young’s double slits experiment, the position of 5th bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 nm. The separation between the slits is : 

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a

60μm

b

48μm

c

12μm

d

36μm

answer is A.

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Detailed Solution

D = 1m, λ=6000×10−10m

N = 5, yn=nλDd=5×6000×10−10×1d=5cm

d=5×6000×10−105×10−2

=6000×10−8=60×10−6m

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