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In Young’s double slits experiment, the position of 5^th bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 nm. The separation between the slits is :

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$60 μ m$

$48 μ m$

$12 μ m$

$36 μ m$

answer is A.

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Detailed Solution

D = 1m, $λ = 6000 \times 10^{- 10} m$

N = 5, $y_{n} = \frac{n λ D}{d} = \frac{5 \times 6000 \times 10^{- 10} \times 1}{d} = 5 c m$

$d = \frac{5 \times 6000 \times 10^{- 10}}{5 \times 10^{- 2}}$

$= 6000 \times 10^{- 8} = 60 \times 10^{- 6} m$

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