In Zeisel’s method for the determination of methoxy groups a sample of 2.68g of a compound (A) gave 14.08g of AgI. If the molecular weight of compound (A) is 134. Then the number of $(- O C H_{3})$ groups in the compound (A) is (round off nearest integer) (atomic weights of Ag=108, I=127, C=12, O=16, H=1)

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answer is 3.

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Detailed Solution

No. of moles of compound $A = \frac{2.68}{134} = 0.02$
No. of moles of AgI = $\frac{14.08}{235} = 0.06$
i.e. 1 mole of a gives 3 moles of AgI, i.e. three $- 0, H_{3}$ groups are present

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