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Q.

In zinc blende structure, $Z n^{+ 2}$ ions are present in altemate tetrahedral voids and $S^{- 2}$ in $CCP$ . The The effective atomic number of $Z n^{+ 2}$ and $S^{- 2}$ are respectively

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a

4,3

b

4,4

c

3,4

d

4,5

answer is B.

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Detailed Solution

Since $S^{- 2}$ occupies $CCP$ .

Number of $S^{2 -} = 8 \times \frac{1}{8} + 6 \times \frac{1}{2} = 4$

$Z n^{+ 2}$ Occupies alternate tetrahedral voids

$Z n^{2 +} = 8 \times \frac{1}{2} = 4$

The effective atomic number of $Z n^{+ 2}$ and $S^{- 2}$ are 4,4

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