In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is

$\mathrm{Dominant}\text{ allelic }\left(\mathrm{A}\right)\text{ frequency = p }$

$\text{= }\frac{2\text{ (number of homozygous dominant individuals) + number of heterozygous individuals}}{2\text{ (Total number of individuals in the population)}}$

$=\frac{2\left(360\right)+480}{2\left(1000\right)}=\frac{1200}{2000}=0.6$