In $\mathrm{a}∆\mathrm{ABC} ;$ if $2 \mathrm{Sin} \mathrm{A}+\sqrt{3}\mathrm{SinB} = \frac{5}{2}$ and $\sqrt{3}\mathrm{Sin} \mathrm{A}+2 \mathrm{SinB}=\frac{3\sqrt{3}}{2}$ then $\mathrm{C} =$

$$\begin{gathered} 2\sin \mathrm{A}+\sqrt{3} \sin \mathrm{B}=\frac{5}{2} -\left(1\right) \\ \sqrt{3} \sin \mathrm{A}+2 \sin \mathrm{B}=\frac{3\sqrt{3}}{2} -\left(2\right) \end{gathered}$$

Solving (1) and (2)

$$\begin{gathered} \sin \mathrm{A}=\frac{1}{2} \sin \mathrm{B}=\frac{\sqrt{3}}{2} \\ \mathrm{A}={30}^0 \mathrm{B}={60}^0, \mathrm{C}={90}^0 \end{gathered}$$