In ΔABC, if ∠C=90∘, then a+cb+b+ca is

a+cb+b+ca=a2+b2+ac+bcab=c2(a+b+c)abc=c2(2s)4RΔ=2Rr=cr

In ΔABC, if ∠C=90∘, then a+cb+b+ca is

a+cb+b+ca=a2+b2+ac+bcab=c2(a+b+c)abc=c2(2s)4RΔ=2Rr=cr

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In $Δ A B C, if ∠ C = 90^{\circ}, then \frac{a + c}{b} + \frac{b + c}{a}$ is

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c/r

1/2Rr

R/r

answer is A.

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$\frac{a + c}{b} + \frac{b + c}{a} = \frac{a^{2} + b^{2} + a c + b c}{a b} = \frac{c^{2} (a + b + c)}{a b c} = \frac{c^{2} (2 s)}{4 R Δ} = \frac{2 R}{r} = \frac{c}{r}$

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In ΔABC, if ∠C=90∘, then a+cb+b+ca is

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In $Δ A B C, if ∠ C = 90^{\circ}, then \frac{a + c}{b} + \frac{b + c}{a}$ is