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Q.

In ABC, with usual notation, the value of the expression r=0nncrarbn-r cosrB-(n-r)A is

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a

bn

b

an

c

cn

d

0

answer is A.

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Detailed Solution

  r=0n cr  n ar bn-r ei (rB-(n-r)A) =r=0n cr  n a ei br be-iAn-rr=0  a eiB+be-iAn =a cos B+i a sin B+b cos A-i b sin An

From Sine Rule

  a cos B+i a sin B+b cos A-i a sin An =(a cos B+b cos A)n =cn

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