In $∆$ABC,P,Q,R are points on $\overline{\mathrm{BC}},\overline{\mathrm{CA}},\overline{\mathrm{AB}}$ respectively, dividing them in the ratio 1:4, 3:2 and 3:7 the point S divides AB in the ratio 1:3 then $\frac{|\overline{\mathrm{AP}}+\overline{\mathrm{BQ}}+\overline{\mathrm{CR}}|}{\left|\overline{\mathrm{CS}}\right|}=$