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Q.

In a PNP transistor working as a common-base amplifier, current gain is 0.96 and emitter current is 7.2 rnA. The base current is

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a

0.2 rnA

b

0.35 rnA

c

0.4 rnA

d

0.29 rnA

answer is C.

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Detailed Solution

α=icie=0.96  and ie=7.2 mA ic=0.96×ie=0.96×7.2=6.91 mA ∴ie=ic+ib⇒7.2=6.91+ib⇒ib=0.29 mA

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