In ${\mathrm{B}}_3{\mathrm{N}}_3{\mathrm{H}}_6$ compound, the correct option is (State 'T' for True and 'F" for False):

In ${\mathrm{B}}_3{\mathrm{N}}_3{\mathrm{H}}_6$ compound, the correct option is '3' $p\pi -p\pi$ bond is present. It can show back bonding.

Due to the significant difference in electronegativity between the boron and nitrogen atoms, borazine is a strongly polar compound. ${\mathrm{B}}_3{\mathrm{N}}_3{\mathrm{H}}_6$ is non-polar with polar bonds. It has lumphy modes at nitrogen atom.

Here, first two statements are correct while other two are incorrect. Hence, option A is correct.