In BCl3 molecule, the Cl-B-Cl bond angle is

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In ${BCl}_{3}$ molecule, the $Cl - B - Cl$ bond angle is

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90⁰

120⁰

190⁰.28'

180⁰

answer is B.

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Detailed Solution

Boron is the central atom. It has three valence electrons. These electrons combine with the electrons of chlorine atoms and form three B-Cl bonds. So, there is ${sp}^{2}$ hybridization and trigonal planar shape. The bond angle in the molecule is $120^{o}$ .
${BCl}_{3} : B \to {SP}^{2} \to Trigonal planer$