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Incident photon energy on metal plate is 7 eV. The maximum K.E of emitted photo electrons is 2 eV. The work function of the plate is

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5 eV

1.7 eV

1 eV

3 eV

answer is A.

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Detailed Solution

$\begin{array}{l} ϕ_{_{0}} = h υ - M a x k . E \\ = 7 - 2 = 5 e V \end{array}$

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