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Incorrect matched pair is :

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${XeO}_{2} F_{2^{-}} s p^{3} d -$ hybridized with one lone pair on $Xe$

$I (CN)_{2}^{⊖} - s p^{3} d$ and $sp -$ hybridized on 'I' and 'C' respectively

${XeF}_{5}^{⊖} - s p^{3} d^{3}$ hybridized with two lone pairs on $Xe$

None of these

answer is D.

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Detailed Solution

One lone pair is present in the ${sp}^{3} d$ hybridization of the ${XeO}_{2} F_{2}$ molecule.

The hybridization of $I (CN)_{2}^{⊖}$ is ${sp}^{3}$ .

Two non-bonding electron pairs, one above and one below the plane, are present in ${XeF}_{5}^{⊖}$ . A pentagon-shaped arrangement of five fluorine atoms is present.

Hence, all the given options are correct.

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