Incorrect set of quantum numbers from the following is :

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$\begin{aligned} n = 4, l = 2, m_{l} = - 2, - 1, 0, + 1, + 2 \\ m_{s} = - 1 / 2 \end{aligned}$

$n = 5, l = 2, m_{l} = - 2, - 1, + 1, + 2, + 3, m_{s} = + 1 / 2$

$\begin{aligned} n = 5, l = 3, m_{l} = - 3, - 2, - 1, 0, + 1, + 2, + 3, \\ m_{s} = + 1 / 2 \end{aligned}$

$\begin{array}{l} n = 4, l = 3, m_{l} = - 3, - 2, - 1, 0, + 1, + 2, + 3, \\ m_{s} = - 1 / 2 \end{array}$

answer is B.

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Detailed Solution

Value of m = –l to +l
for l = 2, m = –2, –1, 0, +1, +2
As option (2) also has +3 value in m, this is the incorrect set of quantum numbers.
(1) n = 4, l = 3 (correct, because l value less than n and l = 3 corresponds to f-orbital). Value of m lies in range from –l to +l. correct set.
(3) n = 4, l = 2 (correct value of n and l, l = 2 corresponds d –orbital). Value of m lies in range – to +l, correct set.
(4) n = 5, l = 3 (correct value of l and m, l = 3 corresponds to f–orbital). Value of m lies in range –l to +l, correct set.

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