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$Increasing order of bond angle of ({Cl}_{2} O, {ClO}_{2}, {Cl}_{2} O_{7}, I_{3}^{⊖}) is$

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a

$I_{3}^{⊖} < {Cl}_{2} O_{7} < {ClO}_{2} < {Cl}_{2} O$

b

${Cl}_{2} O < {Cl}_{2} O_{7} < {ClO}_{2} < I_{3}^{-}$

c

${Cl}_{2} O < {ClO}_{2} < I_{3}^{⊖} < {Cl}_{2} O_{7}$

d

${Cl}_{2} O < {ClO}_{2} < {Cl}_{2} O_{7} < I_{3}^{⊖}$

answer is A.

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Oxides of chlorine, Compounds of chlorine, By OpenStax (Page 2/2) | Jobilize

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Increasing order of bond angle of Cl2O,ClO2,Cl2O7,I3⊖ is