India plays two matches each with West Indies and Australia. In any match, the probabilities of India getting
points 0, 1 and 2 are 0.45, 0.05 and 0.50, respectively. Assuming that the outcomes are independent, the probability
of India getting at least 7 points is

P(at least 7 points) = P(7 points) + P(8 points)

['.' at most 8 points can be scored]

Now, 7 points can be scored by scoring 2 points in 3 matches and 1 point in one match. Similarly, 8 points can be scored by
scoring 2 points in each of 4 matches. Therefore, the required probability is

$\begin{array}{l}{ }^4{C}_1\times \left[P\right(2\text{ points }\left){]}^{3}P\right(1\text{ point })+[P\left(2\text{ points }\right){]}^4\\ =4(0.5{)}^3\times 0.05+(0.50{)}^4\\ =0.0250+0.0625=0.0875\end{array}$